10+81x^2=14

Solution for 10+81x^2=14 equation:

10+81x^2=14

We move all terms to the left:

10+81x^2-(14)=0

We add all the numbers together, and all the variables

81x^2-4=0

a = 81; b = 0; c = -4;
Δ = b2-4ac
Δ = 02-4·81·(-4)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-36}{2*81}=\frac{-36}{162}
=-2/9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+36}{2*81}=\frac{36}{162}
=2/9
$